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Question

Mathematics Question on Relations and functions

Let R=(1,3),(4,2),(2,4),(2,3),(3,1)R = \\{(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)\\} be a relation on the set A=1,2,3,4A = \\{1, 2, 3, 4\\}. The relation R is

A

a function

B

transitive

C

not symmetric

D

reflexive

Answer

not symmetric

Explanation

Solution

Let R=(1,3),(4,2),(2,4),(2,3),(3,1)R = \\{(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)\\} be a relation on the set A=1,2,3,4A = \\{1, 2, 3, 4\\}.

Then

(a) Since (2,4)R (2, 4) \in R and (2,3)RR(2, 3) \in R\:\: \therefore R is not a function

(b) Since (1,3)R(1, 3) \in R and (3,1)R(3, 1) \in R but (1,1)R(1, 1) \therefore R \:\: is not transitive.

(c) Since (2,3)R(2, 3) \in R but (3,2)RR(3, 2) \notin\,R\,\therefore R is not symmetric.

(d) Since (4,4)RR(4, 4) \notin R \therefore R is not reflexive

\therefore RR not symmetric holds.

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