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Question

Mathematics Question on Relations and functions

Let Q+Q^+ be the set of all positive rational numbers. Let \ast be an operation on Q+Q^+ defined by ab=ab2a,bQ+a \ast b = \frac{ab}{2} \forall \, a,b \in Q^+. Then, the identity element in Q+Q^+ for the operation \ast is:

A

0

B

1

C

2

D

12\frac{1}{2}

Answer

2

Explanation

Solution

Let, e be required identity element in Q+Q^+ for the operation \ast.  ae=ea=a\Rightarrow \ a \ast e = e \ast a = a .....(1) Now, ae=ae2a \ast e = \frac{ae}{2} ......(2) (By defn. of ab=ab2a \ast b = \frac{ab}{2} (given)) and ea=ea2e \ast a = \frac{ea}{2} .....(3) \therefore From equation (1) and (2) we have ae2=a\frac{ae}{2} = a  e=2\Rightarrow \ e = 2 Thus, identity element in Q+Q^+ for ab=ab2a \ast b = \frac{ab}{2} is 2.