Question

Let PS be the median of the triangle with vertices $P ( 2,2 ) , Q ( 6 , - 1 )$ and R(7, 3). The equation of the line passing through (1, – 1) and parallel to PS is

• A. $2 x - 9 y - 7 = 0$
• B. $2 x - 9 y - 11 = 0$
• C. $2 x + 9 y - 11 = 0$
• D. $2 x + 9 y + 7 = 0$

Answer 1

Answer: (D)

$2 x + 9 y + 7 = 0$

Answer 2

S = mid point of $Q R = \left( \frac { 6 + 7 } { 2 } , \frac { - 1 + 3 } { 2 } \right) = \left( \frac { 13 } { 2 } , 1 \right)$

$\therefore$ Slope (m) of PS = $\frac { 2 - 1 } { 2 - \frac { 13 } { 2 } } = \frac { - 2 } { 9 }$;

$y + 1 = \frac { - 2 } { 9 } ( x - 1 )$ ⇒ $2 x + 9 y + 7 = 0$