Question

Let P(–1, 0), Q(0, 0) and R (3, $3 \sqrt { 3 }$ ) be three points. Then the equation of the bisector of the angle PQR is-

• A. $\frac { \sqrt { 3 } } { 2 }$ x + y = 0
• B. x + $\sqrt { 3 }$y = 0
• C. $\sqrt { 3 }$ x + y = 0
• D. x + $\frac { \sqrt { 3 } } { 2 }$ y = 0

Answer 1

Answer: (B)

x + $\sqrt { 3 }$y = 0

Answer 2

slope of QR = $\frac { 3 \sqrt { 3 } - 0 } { 3 - 0 }$= $\sqrt { 3 }$

\ equation of line

y – 0 =

$\frac { - 1 } { \sqrt { 3 } }$(x – 0)

x + $\sqrt { 3 }$ y = 0