Question

Let P = $\left[\begin{matrix} \frac{\sqrt3}{2} & \frac{1}{2} \\\ -\frac{1}{2} & \frac{\sqrt3}{2} \end{matrix}\right]$ A = $\left[\begin{matrix} 1 & 1 \\\ 0 & 1 \end{matrix}\right]$ and Q = PAPT. If PTQ2007P = $\left[\begin{matrix} a & b \\\ c & d \end{matrix}\right]$, then 2a+b-3c-4d equal to

• A. 2004
• B. 2005
• C. 2006
• D. 2007

Answer 1

Answer: (B)

2005

Answer 2

The correct option is(B): 2005