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Question

Mathematics Question on Plane

Let PP be the plane, passing through the point (1,1,5)(1,-1,-5) and perpendicular to the line joining the points (4,1,3)(4,1,-3) and (2,4,3)(2,4,3). Then the distance of PP from the point (3,2,2)(3,-2,2) is

A

6

B

4

C

5

D

7

Answer

5

Explanation

Solution

Equation of Plane :
2(x−1)−3(y+1)−6(z+5)=0
Or 2x−3y−6z=35
⇒ Required distance =
4+9+36​∣2(3)−3(−2)−6(2)−35∣​
=5
So, the correct option is (C) : 5