Question
Mathematics Question on Plane
Let P be the plane, passing through the point (1,−1,−5) and perpendicular to the line joining the points (4,1,−3) and (2,4,3). Then the distance of P from the point (3,−2,2) is
A
6
B
4
C
5
D
7
Answer
5
Explanation
Solution
Equation of Plane :
2(x−1)−3(y+1)−6(z+5)=0
Or 2x−3y−6z=35
⇒ Required distance =
4+9+36∣2(3)−3(−2)−6(2)−35∣
=5
So, the correct option is (C) : 5