Question

Let $P_1$ and $P_2$ be two planes given by $P_1: 10 x+15 y+12 z-60=0,$ $P_2:-2 x+5 y+4 z-20=0$ Which of the following straight lines can be an edge of some tetrahedron whose two faces lie on $P_1$ and $P_2$ ?

• A. $\frac{x-1}{0}=\frac{y-1}{0}=\frac{z-1}{5}$
• B. $\frac{x-6}{-5}=\frac{y}{2}=\frac{z}{3}$
• C. $\frac{x}{-2}=\frac{y-4}{5}=\frac{z}{4}$
• D. $\frac{x}{1}=\frac{y-4}{-2}=\frac{z}{3}$

Answer 1

Answer: (D)

$\frac{x}{1}=\frac{y-4}{-2}=\frac{z}{3}$

Answer 2

D

$\frac{x}{1}=\frac{y-4}{-2}=\frac{z}{3}$