Question

Let $\overset{\rightarrow}{C} = \overset{\rightarrow}{A} + \overset{\rightarrow}{B}$ then

• A. $|\overset{\rightarrow}{C|}$ is always greater then $|\overset{\rightarrow}{A}|$
• B. It is possible to have $|\overset{\rightarrow}{C}| < |\overset{\rightarrow}{A}|$ and $|\overset{\rightarrow}{C}| < |\overset{\rightarrow}{B}|$
• C. C is always equal to A + B
• D. C is never equal to A + B

Answer 1

Answer: (B)

It is possible to have $|\overset{\rightarrow}{C}| < |\overset{\rightarrow}{A}|$ and $|\overset{\rightarrow}{C}| < |\overset{\rightarrow}{B}|$

Answer 2

$\overrightarrow{C} + \overrightarrow{A} = \overrightarrow{B}$.

The value of C lies between $A - B$ and $A + B$

∴ $|\overrightarrow{C}|\mspace{6mu} < \mspace{6mu}|\overrightarrow{A}|\mspace{6mu}\mspace{6mu}\text{or}\mspace{6mu}\mspace{6mu}|\overrightarrow{C}|\mspace{6mu} < \mspace{6mu}|\overrightarrow{B}|$