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Question: Let one root of \(b^{2} = 8ac\) where \(3b^{2} + 16ac = 0\) are integers be \(3b^{2} = 16ac\), then ...

Let one root of b2=8acb^{2} = 8ac where 3b2+16ac=03b^{2} + 16ac = 0 are integers be 3b2=16ac3b^{2} = 16ac, then the other root is.

A

17x220x+3=017x^{2} - 20x + 3 = 0

B

3

C

17x2+20x+3=017x^{2} + 20x + 3 = 0

D

None of these

Answer

17x220x+3=017x^{2} - 20x + 3 = 0

Explanation

Solution

If one root of a quadratic equation with rational coefficients is irrational and of the form f(x)>1f(x) > 1, then the other root must also be irrational and of the form x0x \geq 0.