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Question

Mathematics Question on Relations and functions

Let nn be a fixed positive integer. Let a relation RR be defined in II (the set of all integers) as follows : aRbaRb iff n(ab)n|(a - b), that is, iff aa - bb is divisible by nn. Then, the relation RR is

A

Reflexive only

B

Symmetric only

C

Transitive only

D

An equivalence relation

Answer

An equivalence relation

Explanation

Solution

Reflexive : Since for any integer aa, we have aa=0a - a = 0 is divisible by nn. Hence, aRaaIaRa \,\forall a \in I. R\therefore R is Reflexive. Symmetric : Let aRbaRb. Then, by definition of RR, ab=nka - b = nk, where kIk \in I. ba=(k)nb - a = (-k) n where kI- k \in I and so bRabRa. R\therefore R is symmetric. Transitive : Let aRbaRb and bRcbRc. Then, by definition of RR, we have, ab=k1na - b = k_1n and bc=k2nb - c = k_2n, where k1k_1, k2Ik_2 \in I. Then it follows that ac=(ab)+(bc)=k1n+k2n(k1+k2)na - c = (a - b) + (b - c) = k_1n + k_2n - (k_1 + k_2)n, where k1+k2Ik_1 + k_2 \in I and so aRcaRc. R\therefore R is transitive. Hence, RR is an equivalence relation.