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Question: Let \(A = [ x : x \in R , | x | < 1 ]\) \(B = [ x : x \in R , | x - 1 | \geq 1 ]\) and ![](https:/...

Let A=[x:xR,x<1]A = [ x : x \in R , | x | < 1 ] B=[x:xR,x11]B = [ x : x \in R , | x - 1 | \geq 1 ] and

then the set D is

A

[x:1<x2][ x : 1 < x \leq 2 ]

B

C

[x:1x2][ x : 1 \leq x \leq 2 ]

D

None of these

Answer

Explanation

Solution

A=[x:xR,1<x<1]A = [ x : x \in R , - 1 < x < 1 ] \therefore AB=RDA \cup B = R - D

Where D = [x:xR,1x<2][ x : x \in R , 1 \leq x < 2 ]