Question
Mathematics Question on Matrices and Determinants
Let M= β1Β βa\0ββ12β1β0β11ββIf a non-zero vector π=(π₯, π¦, π§)Tββ3 satisfies π6π=π, then a subspace of β3 that contains the vector π is
A
{(π₯, π¦, π§)πββ3 βΆ π₯=0, π¦+π§=0}
B
{(π₯, π¦, π§) πβ β3 βΆπ¦ = 0, π₯+π§=0}
C
{(π₯, π¦, π§) π β β3 βΆ π§=0, π₯+π¦=0}
D
{(π₯, π¦, π§) π β β3 βΆπ₯=0, π¦βπ§=0}
Answer
{(π₯, π¦, π§) πβ β3 βΆπ¦ = 0, π₯+π§=0}
Explanation
Solution
The correct option is (B): {(π₯, π¦, π§) πβ β3 βΆπ¦ = 0, π₯+π§=0}