Question

Let $m$ and $n$ be natural numbers such that $n$ is even and $0.2<\frac{m}{20}$, $\frac{n}{m}$, $\frac{n}{11}<0.5$. Then $m-2n$ equals

• A. 3
• B. 4
• C. 1
• D. 2

Answer 1

Answer: (C)

1

Answer 2

Given $0.2<\frac{m}{20}<0.5$
$⇒ 4<m<10$
$0.2<\frac{n}{11}<0.5$
$⇒ 2.2<n<5.5 ⇒ n=4$
Since $0.2<\frac{n}{m}<0.5$ and $n=4, m=9$
$m-2n=9-2×4=1$
So, the correct answer is (C): $1$