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Question

Question: Let L<sub>1</sub>L<sub>2</sub> be the latusrectum of y<sup>2</sup> = 12x and p be any point on the d...

Let L1L2 be the latusrectum of y2 = 12x and p be any point on the directrix, then the area of ∆P L1L2 is

A

36 sq.units.

B

30 sq.units.

C

26 sq.units.

D

16 sq.units.

Answer

36 sq.units.

Explanation

Solution

From the diagram, area of ∆PLL1 = 12(LL1)(PM)\frac{1}{2}(LL^{1})(PM)

= 126mu(4a)6mu(2a)\frac{1}{2}\mspace{6mu}(4a)\mspace{6mu}(2a)

= 4a2

= 4 x 9 = 36