Question

Let $\left(\frac{x}{2}-1, \frac{y}{9}+1\right)=\left(2, 1\right)$ then the values of $x$ and $y$ respectively are

• A. $3$, $5$
• B. $6$, $0$
• C. $5$, $3$
• D. $0$, $6$

Answer 1

Answer: (B)

$6$, $0$

Answer 2

We have, $\frac{x}{2}-1=2$, $\frac{y}{9}+1=1$ $\Rightarrow x=6$, $y=0$