Question

Let λ1,λ2 be the values of λ for which the points $(\frac{5}{2},1,λ)$ and (-2, 0, 1) are at equal distance from the plane 2x+3y-6z+7=0. If λ1>λ2, then the distance of the point (λ1-λ2,λ2,λ1) from the line $\frac{x-5}{1}=\frac{y-1}{2}=\frac{z+7}{2}$is______.

Answer 1

The answer is: 9