Question
Question: Let I<sub>n</sub> = \(\int _ { 0 } ^ { \pi / 4 } \tan ^ { n }\) x dx. Then I<sub>2</sub> + I<sub>4<...
Let In = ∫0π/4tann x dx. Then I2 + I4, I3 + I5, I4 + I6, I5 + I7, …… are in –
A
A.P.
B
G.P.
C
H.P.
D
None of these
Answer
H.P.
Explanation
Solution
We have for r ³ 1,
Ir + Ir + 2 = ∫0π/4tanr x (1 + tan2 x)dx
= ∫0π/4tanr x sec2 x dx
= tanr + 1 x ]0π/4 =
Thus, the given sequence becomes, 31,41,51,61,…
Which is clearly in H.P.