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Question: Let \(\mathbf { a } = 2 \mathbf { i } + \mathbf { j } - 2 \mathbf { k }\) and \(\mathbf { b } = \mat...

Let a=2i+j2k\mathbf { a } = 2 \mathbf { i } + \mathbf { j } - 2 \mathbf { k } and b=i+j\mathbf { b } = \mathbf { i } + \mathbf { j } If c is a vector such that and the angle between (a×b)( \mathbf { a } \times \mathbf { b } ) and c is 3030 ^ { \circ }, then (a×b)×c=| ( \mathbf { a } \times \mathbf { b } ) \times \mathbf { c } | =

A

23\frac { 2 } { 3 }

B

32\frac { 3 } { 2 }

C

2

D

3

Answer

32\frac { 3 } { 2 }

Explanation

Solution

a×b=ijk212110=2i2j+k\mathbf { a } \times \mathbf { b } = \left| \begin{array} { c c c } \mathbf { i } & \mathbf { j } & \mathbf { k } \\ 2 & 1 & - 2 \\ 1 & 1 & 0 \end{array} \right| = 2 \mathbf { i } - 2 \mathbf { j } + \mathbf { k }

a×b=4+4+1=3\therefore | \mathbf { a } \times \mathbf { b } | = \sqrt { 4 + 4 + 1 } = 3

ca=22ca2=(ca)2=8| \mathbf { c } - \mathbf { a } | = 2 \sqrt { 2 } \Rightarrow | \mathbf { c } - \mathbf { a } | ^ { 2 } = ( \mathbf { c } - \mathbf { a } ) ^ { 2 } = 8

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