Question

Let H be the orthocentre of triangle ABC then angle

subtended by side BC at the centre of in-circle of ∆CHB is-

• A. $\frac{A}{2}$+ 90
• B. $\frac{B + C}{2}$+ 90
• C. $\frac{B - C}{2}$+ 90
• D. None of these

Answer 1

Answer: (B)

$\frac{B + C}{2}$+ 90

Answer 2

∠BIC = 180 – $\frac{90 - C}{2}$– $\frac{90 - B}{2}$

= $\frac{B + C}{2}$+ 90