Question

Let $\gamma_1$ be the ratio of molar specific heat at constant pressure and molar specific heat at constant volume of a monoatomic gas and $\gamma_2$ be the similar ratio of diatomic gas Considering the diatomic gas molecule as a rigid rotator, the ratio, $\frac{\gamma_1}{\gamma_2}$ is :

• A. $\frac{21}{25}$
• B. $\frac{25}{21}$
• C. $\frac{35}{27}$
• D. $\frac{27}{35}$

Answer 1

Answer: (B)

$\frac{25}{21}$

Answer 2

The correct answer is (B) : $\frac{25}{21}$
For monoatomic gas γ1​=35​
For diatomic gas at low temperatures
γ2​=57​
∴γ2​γ1​​=57​35​​=2125​