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Question

Mathematics Question on limits and derivatives

Let g(x)=(x1)nlogcosm(x1);0<x<2,mg(x) = \frac{(x -1)^n}{\log \cos^m (x -1)} ; 0 < x < 2 , m and nn are integers, m \neq 0, n > 0 , and let pp be the left hand derivative of x1|x - 1| at x=1x = 1. If limx1+g(x)=p\displaystyle \lim_{x \to 1^{+}} \, g(x) = p , then

A

n=1,m=1n = 1, m = 1

B

n=1,m=1n = 1, m = - 1

C

n=2,m=2n = 2, m = 2

D

n>2,m=n n > 2, m = n

Answer

n=2,m=2n = 2, m = 2

Explanation

Solution

Answer (c) n=2,m=2n = 2, m = 2