Question
Mathematics Question on limits and derivatives
Let g(x)=logcosm(x−1)(x−1)n;0<x<2,m and n are integers, m = 0, n > 0 , and let p be the left hand derivative of ∣x−1∣ at x=1. If x→1+limg(x)=p , then
A
n=1,m=1
B
n=1,m=−1
C
n=2,m=2
D
n>2,m=n
Answer
n=2,m=2
Explanation
Solution
Answer (c) n=2,m=2