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Question

Question: Let g be the acceleration due to gravity at earth's surface and K be the rotational kinetic energy o...

Let g be the acceleration due to gravity at earth's surface and K be the rotational kinetic energy of the earth. Suppose the earth's radius decreases by 2% keeping all other quantities same, then

A

g decreases by 2% and K decreases by 4%

B

g decreases by 4% and K increases by 2%

C

g increases by 4% and K increases by 4%

D

g decreases by 4% and K increases by 4%

Answer

g increases by 4% and K increases by 4%

Explanation

Solution

g=GMR2g = \frac { G M } { R ^ { 2 } }and K=L22IK = \frac { L ^ { 2 } } { 2 I }

If mass of the earth and its angular momentum remains constant then g1R2g \propto \frac { 1 } { R ^ { 2 } } and K1R2K \propto \frac { 1 } { R ^ { 2 } } i.e. if radius of earth decreases by 2% then g and K both increases by 4%.

(g=GMR2g = \frac { G M } { R ^ { 2 } }rFkk K=L22IK = \frac { L ^ { 2 } } { 2 I }