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Question: Let f(x) = \(y = \frac{1}{\log_{10}(1 - x)} + \sqrt{x + 2}\) Then f(x) is continuous at x = 4 when...

Let f(x) = y=1log⁡10(1−x)+x+2y = \frac{1}{\log_{10}(1 - x)} + \sqrt{x + 2}

Then f(x) is continuous at x = 4 when

A

a = 0, b = 0

B

a = 1, b = 1

C

a = – 1, b = 1

D

a = 1, b = – 1

Answer

a = 1, b = – 1

Explanation

Solution

f(x) =

f(4 – h) = f(4) = f(4 + h)

– 1 + a = a + b = 1 + b

b = –1, a = 1