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Question

Question: Let f(x) = x<sup>3</sup> + bx<sup>2</sup> + cx +d ; 0 \< b<sup>2</sup>\< c then f(x) :...

Let f(x) = x3 + bx2 + cx +d ; 0 < b2< c then f(x) :

A

Is strictly increasing

B

Has local maxima

C

Has local minima

D

Is bounded curve

Answer

Is strictly increasing

Explanation

Solution

f(x) = x3 + bx2 + cx + d

dydx\frac{dy}{dx} = 3x2 + 2bx + c

D = 4b2 – 4 × 3 × c = 4(b2 – 3c ), b2 < c = – ve