Question
Question: Let f(x) = \|x\| + \|x – 1\|, then...
Let f(x) = |x| + |x – 1|, then
A
f(x) is continuous at x = 0, as well as at x = 1
B
f(x) is continuous at x = 0, but not at x = 1
C
f(x) is continuous at x = 1, but not at x = 0
D
None of these
Answer
f(x) is continuous at x = 0, as well as at x = 1
Explanation
Solution
f(x) = |x| + |x–1|

continuous and differentiable everywhere