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Question

Question: Let f(x) = \|x\| + \|x – 1\|, then...

Let f(x) = |x| + |x – 1|, then

A

f(x) is continuous at x = 0, as well as at x = 1

B

f(x) is continuous at x = 0, but not at x = 1

C

f(x) is continuous at x = 1, but not at x = 0

D

None of these

Answer

f(x) is continuous at x = 0, as well as at x = 1

Explanation

Solution

f(x) = |x| + |x–1|

continuous and differentiable everywhere