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Question: Let f(x) be a polynomial of degree two and f(x) \> 0 for all x∈R if g(x) = f(x) + f ′(x) + f ″(x) t...

Let f(x) be a polynomial of degree two and

f(x) > 0 for all x∈R if g(x) = f(x) + f ′(x) + f ″(x) then for all x∈R

A

g(x) < 0

B

g(x) > 0

C

g ′(x) > 0

D

g ′(x) < 0

Answer

g(x) > 0

Explanation

Solution

Q f(x) is polynomial of degree two

∴ f(x) = ax2 + bx + c & f(x) > 0 ∀x∈R

∴ a > 0 and D < 0 ⇒ a > 0 and b2 – 4ac < 0 ….(i)

Now g(x) = f(x) + f ′(x) + f ″(x)

g(x) = ax2 + (b + 2a)x + (2a + c + b)

Now D for g(x) is = (b + 2a)2 – 4.a.(2a + c + b)

= b2 – 4ac – 4a2

= < 0 Q [b2 – 4ac < 0 from(i)]

and coeff. of x2 in g(x) = a > 0

∴ g(x) > 0 ∀x∈R