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Question: Let f(x) = ax<sup>3</sup> + bx<sup>2</sup> + ex + d, a ≠ 0. If x<sub>1</sub> and x<sub>2</sub> are t...

Let f(x) = ax3 + bx2 + ex + d, a ≠ 0. If x1 and x2 are the real and distinct roots of f '(x) = 0 then f(x) = 0 will have three real and distinct roots if

A

x1 . x2< 0

B

f(x1) . f(x2) > 0

C

f(x1). f(x2) < 0

D

x1x2 > 0

Answer

f(x1). f(x2) < 0

Explanation

Solution

Clearly for f(x) = 0 to have three real and distinct root, signs of local maximum value and local minimum value of

y = f(x) must be opposite. Thus f(x1) . f(x2) < 0.