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Question: Let f(x) = 2x<sup>3</sup>+ ax<sup>2</sup> + bx – 3cos<sup>2</sup>x is an increasing function for all...

Let f(x) = 2x3+ ax2 + bx – 3cos2x is an increasing function for all x Î R, then

A

a2 – 6b – 18 > 0

B

a2 – 6b + 18 < 0

C

a2 – 3b – 6 < 0

D

a > 0, b > 0

Answer

a2 – 6b + 18 < 0

Explanation

Solution

f(x) = 2x3 + ax2 + bx – 3cos2x

f '(x) = 6x2 + 2ax + b + 3 sin 2x > 0

6x2 + 2ax + b – 3 > 0 as sin 2x ³ – 1

\ 4a2 – 4b(b – 3) < 0 ̃ a2 – 6b + 18 < 0