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Question

Mathematics Question on Relations and functions

Let f : Z→ Z2Z_2, be a homomorphism of groups defined by
f(a)={0,if a is even 1,if a is oddf(a) = \begin{cases} 0, & \quad \text{if } a \text{ is even}\\\ 1, & \quad \text{if } a \text{ is odd} \end{cases}

then Kerf is :

A

The set of all odd integers

B

The set of all even integers

C

The set of all natural numbers

D

The set of all real numbers

Answer

The set of all even integers

Explanation

Solution

The correct option is(B):The set of all even integers