Question

Let f (x , y) = 0 be the equation of a circle. If f (0, l) = 0 has equal roots l= 2, 2 and f (l, 0) = 0 has roots l =$\frac { 4 } { 5 }$, 5 then the centre of the circle is

• A. (2, 29/10)
• B. (29/10, 2)
• C. (– 2, 29/10)
• D. None

Answer 1

Answer: (B)

(29/10, 2)

Answer 2

Given that circle touches to y- axis at (0, 2) point and intersects to the x- axis at (4/5, 0) and (5, 0).

Centre: $\left( \frac { 29 } { 10 } , 2 \right)$