Question
Mathematics Question on Integrals of Some Particular Functions
Let f(x)=∫(x2+1)(x2+3)2xdx If f(3)=21(loge5−loge6), then f(4) is equal to
A
loge17−loge18
B
loge19−loge20
C
21(loge19−loge17)
D
21(loge17−loge19)
Answer
21(loge17−loge19)
Explanation
Solution
Put x2=t
?(t+1)(t+3)dt?=21??(t+11?-t+31?)dt
f(x)=21?ln(x2+3x2+1?)+C
f(3)=21?(ln10-ln12)+C
?C=0
f(4)=21?ln(1917?)