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Question

Mathematics Question on Trigonometry

Let f(x)=αsin23xf(x)=αsin^23x .If f(π12)f ′(\dfrac{π}{12}) = 3−3,then the value of αα is

A

1-1

B

π\pi

C

π2\dfrac{\pi}{2}

D

11

E

π-\pi

Answer

1-1

Explanation

Solution

Given that:

f(x)=αsin23f(x) = α sin^23

derivate both side with respect to xx$$

f(x)=3αsin6x\therefore f' (x) = 3α sin 6x

f(π12)=3f ′ (\dfrac{π}{12}) = −3 \therefore (Sin(π2=1)Sin(\dfrac{\pi}{2}=1))

3αsin(π2)=33α sin(\dfrac{π}{2}) = −3

α=1α = −1 (_Ans)