Question
Question: Let \(f:R \to R\) be defined by \(f\left( x \right) = \left\\{ \begin{gathered} 2x{\text{ }}x > ...
Let f:R→R be defined by f\left( x \right) = \left\\{ \begin{gathered}
2x{\text{ }}x > 3 \\\
{x^2}{\text{ }}1 < x \leqslant 3 \\\
3x{\text{ }}x \leqslant 1 \\\
\end{gathered} \right\\}. Then what is the value of f(−1)+f(2)+f(4)?
A. 9 B. 14 C. 5 D. 10
Solution
Hint- Here, we will proceed by finding the values of the function for some specific values of x (in this case, we will find the values of the function corresponding to x = -1, x = 2 and x = 4) according to the definition of the function given.
Complete step-by-step answer:
The given function is defined as f\left( x \right) = \left\\{ \begin{gathered}
2x{\text{ }}x > 3 \\\
{x^2}{\text{ }}1 < x \leqslant 3 \\\
3x{\text{ }}x \leqslant 1 \\\
\end{gathered} \right\\}
In f(−1), x = -1 which lies in the interval x⩽1 and for this interval the function is defined as f(x)=3x
By putting x = -1 in the above function, we get
f(−1)=3(−1) ⇒f(−1)=−3 →(1)
In f(2), x = 2 which lies in the interval 1<x⩽3 and for this interval the function is defined as f(x)=x2
By putting x = 2 in the above function, we get
f(2)=22 ⇒f(2)=4 →(2)
In f(4), x = 4 which lies in the interval x>3 and for this interval the function is defined as f(x)=2x
By putting x = 4 in the above function, we get
f(4)=2×4 ⇒f(4)=8 →(3)
The value of the expression f(−1)+f(2)+f(4) can be obtained by using equation
f(−1)+f(2)+f(4)=−3+4+8 ⇒f(−1)+f(2)+f(4)=9
Therefore, the value of f(−1)+f(2)+f(4) is 9.
Hence, option A is correct.
Note- In this particular problem, the given function has three different definitions according to the three intervals. Here, the value of the function for any specific value of x can be calculated by considering the corresponding definition of the function and then substituting that particular value of the variable x.