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Question

Mathematics Question on Functions

Let f:RRf : R \to R be a function defined by f(x)=xmxnf(x) = \frac{x -m}{x-n} , where mnm \neq n, then

A

f is one-one onto

B

f is one-one into

C

f is many-one onto

D

f is many-one into

Answer

f is one-one into

Explanation

Solution

Let f:RRf : R \to R be a function defined by f(x)=xmxnf(x) = \frac{x -m}{x-n} For any (x,y)R (x, y) \in R Let f(x)=f(y)f (x) = f (y) xmxn=ymynx=y\Rightarrow \frac{x-m}{x-n} = \frac{y-m}{y-n} \Rightarrow x =y f \therefore f is one - one Let αR\alpha \in R such that f(x)=αf\left(x\right) = \alpha α=xmxn(xn)α=xm \Rightarrow \alpha = \frac{x-m}{x-n} \Rightarrow \left(x-n\right)\alpha = x-m xαnα=xm\Rightarrow x \alpha-n \alpha=x -m xαx=nαm \Rightarrow x\alpha-x =n\alpha-m x(α1)=nαm \Rightarrow x\left(\alpha-1\right)=n\alpha-m x=nαmα1\Rightarrow x = \frac{n\alpha-m}{\alpha-1} for α=1,xR\alpha=1 , x \notin R So, ff is not onto.