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Question: Let \(f:R\to R\) be a differentiable function at \(c\in R\) and f( c ) = 0. If g(x) = If(x)I, then a...

Let f:RRf:R\to R be a differentiable function at cRc\in R and f( c ) = 0. If g(x) = If(x)I, then at x = c, g is
(a) differentiable if f’(c) = 0
(b) not differentiable
(c) differentiable if f(c)0f'(c)\ne 0
(d) not differentiable if f’(c) = 0

Explanation

Solution

To solve this question, we will first use the definition of differentiability, to find the value of derivative of function g at x = c. then, again we will modify the formula of differentiability for h = 0. And then we will use the concept of differentiability of modulus function. Then, we will discard the options and choose the right option.

Complete step-by-step answer:
Now, in question it is given that f:RRf:R\to R be differentiable function at cRc\in R and f( c ) = 0,
and g(x) = If(x)I.
then the function g at x = c will be
g(c)=limh0g(c+h)g(c)hg'(c)=\displaystyle \lim_{h \to 0}\dfrac{g(c+h)-g(c)}{h} , where h is greater than 0, that is h > 0
Here we have g(x) = I f(x) I
So, g(c)=limh0f(c+h)f(c)hg'(c)=\displaystyle \lim_{h \to 0}\dfrac{\left| f(c+h) \right|-\left| f(c) \right|}{h}
As, it is given that f(c) = 0, so f(c)=0\left| f(c) \right|=0
Then, g(c)=limh0f(c+h)0hg'(c)=\displaystyle \lim_{h \to 0}\dfrac{\left| f(c+h) \right|-0}{h}
g(c)=limh0f(c+h)hg'(c)=\displaystyle \lim_{h \to 0}\dfrac{\left| f(c+h) \right|}{h}
Also, we can write g’(c) as
g(c)=limh0f(c+h)f(c)hg'(c)=\displaystyle \lim_{h \to 0}\left| \dfrac{f(c+h)-f(c)}{h} \right|, where h > 0
g(c)=limh0f(c+h)f(c)hg'(c)=\left| \displaystyle \lim_{h \to 0}\dfrac{f(c+h)-f(c)}{h} \right|
As, limh0f(c+h)f(c)h\displaystyle \lim_{h \to 0}\dfrac{f(c+h)-f(c)}{h} denotes f’(c)
So, we can say that limh0f(c+h)f(c)h=f(c)\left| \displaystyle \lim_{h \to 0}\dfrac{f(c+h)-f(c)}{h} \right|=\left| f'(c) \right|
g(c)=f(c)g'(c)=\left| f'(c) \right|
Or, f is differentiable at x = c
Now, if f’(c) = 0 then g(x) is differentiable at x = c otherwise, left hand derivative say ( LHD )at x = c and right hand derivative ( RHD ) at x = c is different.
Now, also we know that modulus function x\left| x \right| is differentiable everywhere except at x = 0.
So, we can say that g is differentiable at f(c)0f'(c)\ne 0, as we proved above that g is differentiable and equals to g(c)=f(c)g'(c)=\left| f'(c) \right|.

So, the correct answer is “Option c”.

Note: Always remember that if we have to differentiate a function f(x) at point x = a, then we can evaluate the differentiation of f(x) by formula f(a)=limh0f(a+h)f(a)hf'(a)=\displaystyle \lim_{h \to 0}\dfrac{f(a+h)-f(a)}{h}. Also, remember that function x\left| x \right| is differentiable everywhere except at x = 0. Try to choose the correct option by discarding wrong options first.