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Question

Mathematics Question on Functions

Let f:R→Rf:R→R be a function defined by f(x)=x2+9f(x)=x^2+9.The range of ff is

A

RR

B

(−∞,−9]∪[9,∞)(-∞,-9]∪[9,∞)

C

[9,∞)[9,∞)

D

[3,∞)[3,∞)

E

[3,∞)U(−∞,−3][3,∞)\text{U}(-∞,-3]

Answer

[9,∞)[9,∞)

Explanation

Solution

Given that

Let f:R→Rf:R→R be a function defined by f(x)=x2+9f(x)=x^2+9.

So,

f(x)=x2+9f(x) = x^2 + 9

Now, minimum value of f(x)=9f(x) = 9

∴The desires Range is = [9,∞)[9, ∞) (_Ans.)