Question
Mathematics Question on Continuity and differentiability
Let f:R−0,1→R be a function such that f(x)+f(1−x1)=1+x Then f(2) is equal to
A
37
B
29
C
49
D
47
Answer
49
Explanation
Solution
f(x)+f(1−x1)=1+x
x=2⇒f(2)+f(−1)=3
x=−1⇒f(−1)+f(21)=0 (2)
x=21⇒f(21)+f(2)=23(3)
(1)+(3)−(2)⇒2f(2)=29
∴f(2)=49