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Question

Mathematics Question on Functions

Let f:[−4,2]→Rf:[-4,2] \rightarrow \R be given by f(x)=16−x2f(x) = \sqrt{16-x^2}. Then the range of the function f is

A

[0,2]

B

[0,2√3]

C

[0,4]

D

[2√3,4]

E

[-2,2]

Answer

[0,4]

Explanation

Solution

The correct option is (C): [0,4]