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Question

Mathematics Question on integral

Let f(2a - x) = -f(x). then 02af(x)dx=\int\limits^{2a}_{0}f(x)dx=

A

f(x)

B

0

C

20af(x)dx=2^{\int\limits^{a}_{0}f(x)dx=}

D

f(2a-x)

Answer

0

Explanation

Solution

The correct option is (B): 0