Question
Mathematics Question on Differential Calculus
Let f : [1, 2] → R be the function defined by
f(t)=∫1tx2ex2−1 dx.
Then the arc length of the graph of f over the interval [1, 2] equals
A
e2−e
B
e−e
C
e2 - e
D
e2 - 1
Answer
e2−e
Explanation
Solution
The correct option is (A) : e2−e.