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Question

Mathematics Question on Differential Calculus

Let F : [0, 2] → R\R be the function defined by
F(x)=x2x+2ex[t]dt,F(x)=\int_{x^2}^{x+2}e^{x[t]}dt,
where [t] denotes the greatest integer less than or equal to t. Then the value of the derivative of F at x = 1 equals

A

e3 + 2e2 - e

B

e3 - e2 + 2e

C

e3 - e + 2e2

D

e3 + 2e2 + e

Answer

e3 - e + 2e2

Explanation

Solution

The correct option is (C) : e3 - e + 2e2.