Let f : \[-10,10] → R, where f(x) = sin x + \[x2/a] be an od... | MATH - FUNCTIONS | SolveeIt | Solveeit

Today, August 18

Question

Let f : [-10,10] → R, where f(x) = sin x + [x²/a] be an odd function. Then set of values of parameter ‘a’ is/are:

A

(–10, 10) – {0}

B

(0, 10)

C

[100,∞)

D

(100, ∞)

Answer

(100, ∞)

Explanation

Solution

Since f(x) is an odd function, $\left\lbrack \frac{x^{2}}{a} \right\rbrack$ = 0 for all x∈

[-10, 10]

⇒ $0 \leq \frac{x^{2}}{a}$ < 1 for all x∈ [–10, 10] ⇒ a > 100