Question

Let 𝐸1, 𝐸2 and 𝐸3 be three events such that 𝑃(𝐸1∩𝐸2 )=$\frac{1}{4}$ , 𝑃(𝐸1 ∩ 𝐸3 )=𝑃(𝐸2 ∩ 𝐸3 )=$\frac{1}{5}$ and 𝑃(𝐸1 ∩ 𝐸2 ∩ 𝐸3 ) =$\frac{1}{6}$ . Then, among the events 𝐸1 𝐸2 and 𝐸3, the probability that at least two events occur, equals

• A. $\frac{17}{60}$
• B. $\frac{23}{60}$
• C. $\frac{19}{60}$
• D. $\frac{29}{60}$

Answer 1

Answer: (C)

$\frac{19}{60}$

Answer 2

The correct option is (C): $\frac{19}{60}$