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Question

Mathematics Question on Differentiability

Let [.] denote the greatest integer function and f(x)=[tan2x]f (x) = [\tan^2 x], then:

A

limx0f(x)\displaystyle \lim_{x \to 0} f(x) does not exist

B

f(x)f (x) is continuous at x=0x = 0

C

f(x)f (x) is not differentiable at x=0 x = 0

D

f(0)=1f'(0) = 1

Answer

f(x)f (x) is continuous at x=0x = 0

Explanation

Solution

We have f(x)=[tan2x]f (x) = [\tan^2 x]
tan x is an increasing function for π4<x<π4 - \frac{\pi}{4} < x < \frac{\pi}{4}
tan(π4)<tanx<tan(π4)\therefore \, \tan\left(- \frac{\pi}{4}\right) < \tan x < \tan\left(\frac{\pi}{4}\right)
1<tanx<1\Rightarrow-1 < \tan x < 1
0<tan2x<1\Rightarrow 0 < \tan^{2} x < 1
[tan2x]=0\Rightarrow \left[\tan^{2} x\right] = 0
Hence, limx0f(x)=limx0[tan2x]=0\displaystyle \lim_{x \to0} f\left(x\right) =\displaystyle \lim_{x \to0} \left[\tan^{2} x\right] = 0
Also f(0)=0f\left(0\right) = 0
f(x)\therefore f\left(x\right) is continuous at x=0x = 0