Question
Mathematics Question on Coordinate Geometry
Let d be the distance between the parallel lines 3x - 2y + 5 = 0 and 3x - 2y + 5 + 2√13 = 0. Let L1 = 3x - 2y + k1 = 0 (k1 > 0) and L2 = 3x - 2y + k2 = 0 (k2 > 0) be two lines that are at the distance of √134d and √133d from the line 3x - 2y + 5y = 0. Then the combined equation of the lines L1 = 0 and L2 = 0 is:
A
(3x - 2y)2 + 24(3x - 2y) + 143 = 0
B
(3x - 2y)2 + 8(3x - 2y)+ 33 = 0
C
(3x - 2y)2 +12(3x-2y) + 13 = 0
D
(3x - 2y)2 +12(3x-2y) + 1 = 0
Answer
(3x - 2y)2 + 24(3x - 2y) + 143 = 0
Explanation
Solution
The correct option is (A) (3x - 2y)2 + 24(3x - 2y) + 143 = 0