Question
Question: Let C<sub>1</sub>& C<sub>2</sub> are circles defined by x<sup>2</sup> + y<sup>2</sup> – 20x + 64 = 0...
Let C1& C2 are circles defined by x2 + y2 – 20x + 64 = 0 and x2 + y2 + 30x + 144 = 0. The length of shortest line segment PQ which is tangent to C1 at P and C2 at Q is
A
18
B
20
C
22
D
None
Answer
20
Explanation
Solution
Draw OM || PQ
Radius of C1 = r1 = 6
Radius of C2 = r2 = 9
Let OOў = d = 25
Now
d2 = (r1 + r2)2 + l2
\ l = d2−(r1+r2)2
Ю l = 20