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Question: Let C<sub>1</sub>& C<sub>2</sub> are circles defined by x<sup>2</sup> + y<sup>2</sup> – 20x + 64 = 0...

Let C1& C2 are circles defined by x2 + y2 – 20x + 64 = 0 and x2 + y2 + 30x + 144 = 0. The length of shortest line segment PQ which is tangent to C1 at P and C2 at Q is

A

18

B

20

C

22

D

None

Answer

20

Explanation

Solution

Draw OM || PQ

Radius of C1 = r1 = 6

Radius of C2 = r2 = 9

Let OOў = d = 25

Now

d2 = (r1 + r2)2 + l2

\ l = d2(r1+r2)2\sqrt{d^{2} - (r_{1} + r_{2})^{2}}

Ю l = 20