Question

Let C be the circle in the complex plane with centre z0 =$\frac{1}{2}$ (1+3i) and radius r = 1. Let z1 = 1+ i and the complex number z2 be outside the circle C such that |z1 – z0| |z2 – z0| = 1. If z0, z1 and z2 are collinear, then the smaller value of |z2|2 is equal to

• A. $\frac{3}{2}$
• B. $\frac{5}{2}$
• C. $\frac{7}{2}$
• D. $\frac{13}{2}$

Answer 1

Answer: (B)

$\frac{5}{2}$

Answer 2

The correct option is(B): $\frac{5}{2}$