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Question

Mathematics Question on Straight lines

Let CC be the centre of the circle x2+y2x+2y=114x^2+y^2-x+2 y=\frac{11}{4} and PP be a point on the circle A line passes through the point CC, makes an angle of π4\frac{\pi}{4} with the line CP and intersects the circle at the points QQ and RR Then the area of the triangle PQRPQR (in unit 2{ }^2) is :

A

2

B

222 \sqrt{2}

C

8sin(π8)8 \sin \left(\frac{\pi}{8}\right)

D

8cos(π8)8 \cos \left(\frac{\pi}{8}\right)

Answer

222 \sqrt{2}

Explanation

Solution

The correct option is (B): 222\sqrt{2}