Question
Question: Let * be a binary operation, on the set of all non – zero real numbers, given by \[a\text{ }*\text{ ...
Let * be a binary operation, on the set of all non – zero real numbers, given by a ∗ b =5ab , for all a,b∈R−0 . Find the value of x, given that 2∗(x∗5)=10 .
Solution
To solve this question, what we will do is we will apply the mathematical definition of binary operation given in the question on 2∗(x∗5)=10. First we will use binary operation on x*5 and then finally with 2 and hence we will solve for the value of x.
Complete step by step answer:
Before, we solve the question, let see what is binary operation and what does a,b∈R−0means as for solving the given function it is important to know the meaning of binary operation.
Binary operation is a calculation that combines two elements to produce another element and binary operator can be any operation between two numbers.
Let's understand with an example.
We know that 4 + 5 = 9. Now, we can say that two numbers used in binary operation are 4 and 5 and addition ‘ + ‘ is a binary operator and the produced number is 9. This is what binary operation means.
a,b∈R−0, means a , b are any number which belongs to a set of real numbers and which cannot be equal to 0.
Now, in question it is given that * be a binary operation, on the set of all non – zero real numbers, given by a ∗ b =5ab , for all a,b∈R−0 and 2∗(x∗5)=10, so we have to solve for the value of x.
Now, 2∗(x∗5)=10
Applying binary operation a ∗ b =5ab in ( x * 5 ), we get
2∗(5x⋅5)=10
On solving, we get
2∗x=10
Now, Applying binary operation a ∗ b =5ab in ( 2 * x ), we get
52x=10
Solving using we get
x=25
Hence, the value of x is 25.
Note:
For solving such problems, one must know what binary operation actually means. Also, use binary operation on two numbers at a time unless and until other information is given in question as it will reduce the risk of calculation error.