Question

Let awards in event A is 48 and awards in event B is 25 and awards in event C is 18 and also n(A ∪ B ∪ C) = 60, n(A ⋂ B ⋂ C) = 5, then how many got exactly two awards is?

• A. 21
• B. 25
• C. 24
• D. 23

Answer 1

Answer: (A)

21

Answer 2

The correct answer is option (A) : 21

Number of persons who get exactly 2 awards : n(A)+n(B)+n(C)-n(A$\cup$B$\cup$C)-2n(A$\cap$B$\cap$C)
= 48+25+18-60-10
= 21